- Tags: bohr, radius, energy, derivation
- Difficulty: Moderate
For hydrogen-like atom (nuclear charge Ze, one electron): Centripetal force = Coulomb force: mv2/r = kZe2/r2. Angular momentum quantization: mvr = nℏ. From these two equations: r_n = n2ℏ^{2}/(mkZe2) = n2a_{0}/Z, where a_{0} = ℏ^{2}/(mke2) = 0.529 Å. Velocity: v_n = kZe2/(nℏ) = Zv0/n, where v_{0} = ke2/ℏ = $2.18 \times 10^{6}m/s=c/137.Energy:En=−mk^{2}Z2e^{4}/(2n^{2}ℏ2)=−13.6Z^{2}/n^{2}eV.Thenegativeenergyindicatesaboundstate.ThekineticenergyKE=½mv^{2}=kZe^{2}/(2r)=13.6Z^{2}/n^{2}eV(positive).ThepotentialenergyPE=−kZe^{2}/r=−27.2Z^{2}/n^{2}eV.Note:E=KE+PE,andPE=−2KE(virialtheoremfor1/rpotential).
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