Part of ES-01 — Electrostatics

Cornell Notes — Subtopic: Capacitors and Dielectrics

by Notetube Official201 words8 views
Cue / QuestionNotes
Formula for parallel plate capacitor (vacuum)C = ε_{0}A/d
Formula with dielectricC = Kε_{0}A/d; K = dielectric constant (≥1)
Series combination formula1/C_eq = 1/C1C_{1} + 1/C2C_{2} + ...
Parallel combination formulaC_eq = C1C_{1} + C2C_{2} + ...
Which capacitor in series has more energy?Smaller C (since Q same; U = Q2Q^{2}/2C, smaller C → larger U)
Which capacitor in parallel has more energy?Larger C (since V same; U = ½CV2CV^{2}, larger C → larger U)
Three forms of energy storedU = ½CV2CV^{2} = Q2Q^{2}/(2C) = ½QV
Battery connected, plates pulled apart (d doubled)?C halves; Q = CV halves; U = ½CV2CV^{2} halves
Battery disconnected, plates pulled apart (d doubled)?Q stays same; C halves; V doubles; U = Q2Q^{2}/2C doubles

Summary: Capacitor questions in NEET always test either the combination rules or what happens when the battery is connected vs disconnected during modification (dielectric insertion, plate separation change). Master both scenarios: connected → V constant, disconnected → Q constant.

Like these notes? Save your own copy and start studying with NoteTube's AI tools.

Sign up free to clone these notes