Part of ME-02 — Kinematics

Cornell Notes — Kinematics Full Topic

by Notetube Official305 words4 views
Cue / QuestionNotes
What are the 3 equations of motion?v = u + at; s = ut + ½at2at^{2}; v2v^{2} = u2u^{2} + 2as
What does each equation omit?1st omits s; 2nd omits v; 3rd omits t
Formula for displacement in nth second?sn=u+a(2n1)2s_n = u + \frac{a(2n-1)}{2} — unit: m
Projectile: Time of flight formula?T=2usinθgT = \frac{2u\sin\theta}{g} — depends on sin θ
Projectile: Max height formula?H=u2sin2θ2gH = \frac{u^2\sin^2\theta}{2g} — depends on sin2in^{2}θ
Projectile: Range formula?R=u2sin2θgR = \frac{u^2\sin 2\theta}{g} — max at θ = 45°
Complementary angles property?θ and (90°−θ) give same range R; H ratio = tan2an^{2}θ
Velocity at highest point of projectile?Horizontal only: v=ucosθv = u\cos\theta (NOT zero)
Centripetal acceleration formula?ac=v2r=ω2ra_c = \frac{v^2}{r} = \omega^2 r — toward centre
v-t graph: slope and area?Slope = acceleration; Area = displacement
x-t graph: slope?Slope = instantaneous velocity
Sign convention for free fall (upward +ve)?g = −9.8 m/s2s^{2}
Vector resolution formulas?Ax=AcosθA_x = A\cos\theta; Ay=AsinθA_y = A\sin\theta
Scalar product vs vector product?A·B = AB cosθ (scalar); A×B = AB sinθ (vector, ⊥ to both)

Summary: Kinematics covers motion without forces. For constant acceleration, use SUVAT equations (each omits one variable). Projectile motion separates horizontal (constant velocity) from vertical (uniform acceleration under g). Key traps: horizontal velocity is NOT zero at peak; complementary angles share range but differ in height (60° gives 3× the height of 30°). Circular motion keeps speed constant while continuously changing velocity direction. Always fix sign convention at the start and maintain it throughout.

Like these notes? Save your own copy and start studying with NoteTube's AI tools.

Sign up free to clone these notes