Part of ME-06 — Gravitation

Core Formulas with SI Units and Dimensional Analysis

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Complete Formula Reference

Newton's Universal Law

F=Gm1m2r2[G]=[M1 L3 T2]N m2 kg2F = \frac{G m_1 m_2}{r^2} \quad [G] = [\text{M}^{-1}\ \text{L}^3\ \text{T}^{-2}] \quad \text{N m}^2\ \text{kg}^{-2}

Acceleration Due to Gravity at Surface

g=GMR2[M0 L1 T2]m s2g = \frac{GM}{R^2} \quad [\text{M}^0\ \text{L}^1\ \text{T}^{-2}] \quad \text{m s}^{-2}

Key Substitution: GM=gR2GM = gR^2 — eliminates G and M from all satellite problems.

g at Altitude h (exact)

gh=gR2(R+h)2[M0 L1 T2]m s2g'_h = \frac{gR^2}{(R+h)^2} \quad [\text{M}^0\ \text{L}^1\ \text{T}^{-2}] \quad \text{m s}^{-2}

g at Altitude h (approximate, hRh \ll R)

ghg ⁣(12hR)valid only for hRg'_h \approx g\!\left(1 - \frac{2h}{R}\right) \quad \text{valid only for}\ h \ll R

g at Depth d

gd=g ⁣(1dR)[M0 L1 T2]m s2g'_d = g\!\left(1 - \frac{d}{R}\right) \quad [\text{M}^0\ \text{L}^1\ \text{T}^{-2}] \quad \text{m s}^{-2}

g at Latitude λ

geff=gRω2cos2 ⁣λ[M0 L1 T2]m s2g_{\text{eff}} = g - R\omega^2\cos^2\!\lambda \quad [\text{M}^0\ \text{L}^1\ \text{T}^{-2}] \quad \text{m s}^{-2}

Kepler's Third Law

T2=4π2GMr3[M0 L0 T2]s2T^2 = \frac{4\pi^2}{GM}\,r^3 \quad [\text{M}^0\ \text{L}^0\ \text{T}^2] \quad \text{s}^2

Gravitational Potential Energy

U=GMmr[M1 L2 T2]JU = -\frac{GMm}{r} \quad [\text{M}^1\ \text{L}^2\ \text{T}^{-2}] \quad \text{J}

Gravitational Potential

V=GMr[M0 L2 T2]J kg1V = -\frac{GM}{r} \quad [\text{M}^0\ \text{L}^2\ \text{T}^{-2}] \quad \text{J kg}^{-1}

Escape Velocity

ve=2GMR=2gR[M0 L1 T1]m s1v_e = \sqrt{\frac{2GM}{R}} = \sqrt{2gR} \quad [\text{M}^0\ \text{L}^1\ \text{T}^{-1}] \quad \text{m s}^{-1}

Earth: ve11,200 m s1=11.2 km s1v_e \approx 11{,}200\ \text{m s}^{-1} = 11.2\ \text{km s}^{-1}

Orbital Velocity

v0=GMr=gR2r[M0 L1 T1]m s1v_0 = \sqrt{\frac{GM}{r}} = \sqrt{\frac{gR^2}{r}} \quad [\text{M}^0\ \text{L}^1\ \text{T}^{-1}] \quad \text{m s}^{-1}

Near surface: v0=gR7,920 m s1=7.9 km s1v_0 = \sqrt{gR} \approx 7{,}920\ \text{m s}^{-1} = 7.9\ \text{km s}^{-1}

Relation Between Escape and Orbital Velocity

ve=2v0vev0=21.414v_e = \sqrt{2}\,v_0 \quad \Rightarrow \quad \frac{v_e}{v_0} = \sqrt{2} \approx 1.414

Orbital Period

T=2πrv0=2πr3GM[M0 L0 T1]sT = \frac{2\pi r}{v_0} = 2\pi\sqrt{\frac{r^3}{GM}} \quad [\text{M}^0\ \text{L}^0\ \text{T}^1] \quad \text{s}

Near surface: T=2πR/g5,073 s84.6 minT = 2\pi\sqrt{R/g} \approx 5{,}073\ \text{s} \approx 84.6\ \text{min}

Satellite Kinetic Energy

KE=GMm2r=mv022[M1 L2 T2]JKE = \frac{GMm}{2r} = \frac{mv_0^2}{2} \quad [\text{M}^1\ \text{L}^2\ \text{T}^{-2}] \quad \text{J}

Satellite Potential Energy

PE=GMmr=2KE[M1 L2 T2]JPE = -\frac{GMm}{r} = -2KE \quad [\text{M}^1\ \text{L}^2\ \text{T}^{-2}] \quad \text{J}

Satellite Total Energy

E=GMm2r=KE[M1 L2 T2]JE = -\frac{GMm}{2r} = -KE \quad [\text{M}^1\ \text{L}^2\ \text{T}^{-2}] \quad \text{J}

Dimensional Analysis: Deriving G's Dimensions

From F=Gm1m2/r2F = Gm_1 m_2 / r^2:

[G]=[F][r2][m1][m2]=kg m s2m2kgkg=kg1 m3 s2=[M1 L3 T2][G] = \frac{[F][r^2]}{[m_1][m_2]} = \frac{\text{kg m s}^{-2} \cdot \text{m}^2}{\text{kg} \cdot \text{kg}} = \text{kg}^{-1}\ \text{m}^3\ \text{s}^{-2} = [\text{M}^{-1}\ \text{L}^3\ \text{T}^{-2}]

SI Unit Consistency Check for vev_e

ve=2gR  [ve]=m s2m=m2 s2=m s1 v_e = \sqrt{2gR}\ \Rightarrow\ [v_e] = \sqrt{\text{m s}^{-2} \cdot \text{m}} = \sqrt{\text{m}^2\ \text{s}^{-2}} = \text{m s}^{-1}\ \checkmark

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