Part of ME-05 — Rotational Motion

Concept: Angular Momentum Conservation

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Statement

When the net external torque on a system is zero: Ltotal=Iiωi=constant\vec{L}_{total} = \sum I_i\omega_i = \text{constant}

Physical Interpretation

  • Angular momentum is the rotational analogue of linear momentum.
  • Just as F=0p=constF = 0 \Rightarrow p = \text{const}, we have τ=0L=const\tau = 0 \Rightarrow L = \text{const}.

Key Examples

1. Ice skater pulling arms in: Iiωi=IfωfI_i\omega_i = I_f\omega_f; pulling in reduces II, so ω\omega increases.

2. Diver tucking: Off the board, τext0\tau_{ext} \approx 0 (gravity acts through CM). Tucking reduces IIω\omega increases → faster spin.

3. Rotating turntable + person: If the person moves outward, II of system increases → ω\omega decreases.

4. Disc collision: Disc 1 (rotating) + Disc 2 (stationary) dropped coaxially: I1ω1=(I1+I2)ωfI_1\omega_1 = (I_1 + I_2)\omega_fωf<ω1\omega_f < \omega_1

Critical Distinction

Angular momentum conservation does NOT imply kinetic energy conservation.

Since KE=L2/(2I)KE = L^2/(2I) and LL is constant:

  • If II decreases → KEKE increases (e.g., skater)
  • The extra energy comes from internal forces (muscles)

Kinetic energy ratio: KEfKEi=IiIf\frac{KE_f}{KE_i} = \frac{I_i}{I_f}

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