Part of JPC-08 — Mole Concept & Stoichiometry

Combustion Analysis

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For CxHyOz + excess O2 -> x CO2 + y2\frac{y}{2} H2O. Given masses of CO2 and H2O collected: mass C = 1244\frac{12}{44} x mass CO2 = 311\frac{3}{11} x mass CO2. mass H = 218\frac{2}{18} x mass H2O = 19\frac{1}{9} x mass H2O. mass O = mass of sample - mass C - mass H. If N or S present: N -> converted to N2 (measure volume) or absorbed as specific product. S -> SO2 (absorbed in peroxide, titrated). From masses of elements, calculate empirical formula. With molar mass, find molecular formula. Common trap: not accounting for oxygen already present in the compound.

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