Part of JME-03 — Work, Energy & Power

Collisions — Energy Perspective

by Notetube Official82 words2 views

Elastic Collision (KE conserved): \frac{1}{2}$$m_1u12u_1^2 + \frac{1}{2}$$m_2u22u_2^2 = \frac{1}{2}$$m_1v12v_1^2 + \frac{1}{2}$$m_2v22v_2^2

Results (1D, m2m_2 initially at rest): v1v_1 = u1u_1m1m2(m1+m2)\frac{m_1-m_2}{(m_1+m_2)} v2v_2 = 2m1m_1*u1m1+m2\frac{u_1}{m_1+m_2}

Perfectly Inelastic (stick together): v = m1m_1u1m1+m2\frac{u_1}{m_1+m_2} (momentum conservation) KE lost = 12\frac{1}{2}muurel2u_{rel}^2 where mu = m1m_1m2m1+m2\frac{m_2}{m_1+m_2} (reduced mass)

Coefficient of Restitution: e = v2v1(u1u2)\frac{v_2 - v_1}{(u_1 - u_2)} = relative speed of separation / relative speed of approach

  • e = 1: perfectly elastic
  • e = 0: perfectly inelastic
  • 0 < e < 1: partially inelastic

Like these notes? Save your own copy and start studying with NoteTube's AI tools.

Sign up free to clone these notes