NoteTube

Part of JPC-05 — Solutions: Raoult's Law & Colligative Properties

Boiling Point Elevation

by Notetube Official113 words188 views

delta_Tb = i * Kb * m. Kb = molal elevation constant = RTb^2M_solvent/(1000*delta_H_vap). For water: Kb = 0.512 K.kg/mol, Tb = 373 K. Physical explanation: adding non-volatile solute lowers vapour pressure, so a higher temperature is needed to make vapour pressure equal atmospheric pressure. delta_Tb is always positive (boiling point rises). Key: Kb depends only on the solvent, not the solute. Solvents with high Kb: camphor (Kb = 5.95), acetic acid (3.07), benzene (2.53). Higher Kb means greater sensitivity for molar mass determination. For molar mass: M = (i * Kb * w_solute * 1000) / (delta_Tb * w_solvent). If i is unknown, the "apparent" molar mass differs from true molar mass.

Like these notes? Save your own copy and start studying with NoteTube's AI tools.

Sign up free to clone these notes