Part of THERM-01 — Thermodynamics & Kinetic Theory of Gases

Application Note: Engines, Refrigerators, and Real Systems

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Heat Engine

A heat engine converts heat to mechanical work in a cyclic process.

Working:

  1. Absorbs heat Q1Q_{1} from hot reservoir at T1T_{1} (K)
  2. Converts part of it to useful work W
  3. Rejects remaining heat Q2Q_{2} to cold reservoir at T2T_{2} (K)

η=WQ1=Q1Q2Q1=1T2T1\eta = \frac{W}{Q_1} = \frac{Q_1 - Q_2}{Q_1} = 1 - \frac{T_2}{T_1}

Examples: Steam turbine, internal combustion engine, jet engine.

Practical efficiencies: Car engine ≈ 25%, steam turbine ≈ 35–40%, gas turbine ≈ 45%.

Carnot Engine

The ideal (theoretical) engine operating between T1T_{1} and T2T_{2}. No real engine can exceed its efficiency.

  • Carnot cycle: two isothermal + two adiabatic processes
  • All processes are reversible
  • η_Carnot = 1 − T2T_{2}/T1T_{1} is the maximum attainable efficiency

Refrigerator / Heat Pump

Operates in reverse — work is supplied to transfer heat from cold to hot.

COPrefrigerator=Q2W=T2T1T2\text{COP}_{refrigerator} = \frac{Q_2}{W} = \frac{T_2}{T_1 - T_2}

COPheatpump=Q1W=T1T1T2=COPref+1\text{COP}_{heat pump} = \frac{Q_1}{W} = \frac{T_1}{T_1 - T_2} = \text{COP}_{ref} + 1

Real-world example: Air conditioner with T1T_{1} = 310 K (outside), T2T_{2} = 295 K (room): COP=295310295=2951519.7\text{COP} = \frac{295}{310 - 295} = \frac{295}{15} \approx 19.7

For every 1 J of electrical work, 19.7 J of heat is removed from the room — which is why air conditioners are more efficient than electric heaters.

Comparison Table

ParameterHeat EngineRefrigerator
Energy inputQ1Q_{1} from hot reservoirWork W
Useful outputWork WQ2Q_{2} from cold reservoir
Figure of meritη = W/Q1Q_{1} ≤ 1COP = Q2Q_{2}/W > 1 possible
Ideal limitη → 1 only if T2T_{2} → 0 KCOP → ∞ if T1T_{1} = T2T_{2}
Second Law constraintη < 1 (cannot extract all Q1Q_{1})W > 0 required (heat can't flow cold → hot for free)

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