Part of ALG-03 — Sequences & Series (AP, GP, Special Series)

AM-GM-HM Applications in JEE

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Cue Column:

  • When to apply AM-GM?
  • What is the equality condition?
  • How does it help in finding min/max?

Note Column: AM-GM inequality: For positive reals a1a_1, a2a_2, ..., ana_n: a1+a2+...+ann\frac{a_1+a_2+...+a_n}{n} >= (a1a_1a2a_2...*ana_n)^{1/n}

Equality iff a1a_1 = a2a_2 = ... = ana_n.

Finding minimum of sum given constant product: If ab = k (constant), min(a+b) = 2*sqrt(k), achieved when a = b = sqrt(k).

Finding minimum of a + k/a for a > 0: By AM-GM: a + k/a >= 2*sqrt(k), equality when a = sqrt(k).

JEE application: To find the minimum value of (x2x^2 + 1/x2x^2) for x > 0: x2x^2 + 1/x2x^2 >= 2*sqrt(1) = 2, equality when x2x^2 = 1, i.e., x = 1.

Extended: For weighted AM-GM, and for multiple variable optimization, the technique extends naturally.

Summary: AM-GM gives minimum of sum (given product is fixed) and maximum of product (given sum is fixed). Always check equality condition.

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